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Python, how to check if a number is odd or even

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A number is even when divided by 2 the remainder is 0. Think 2, 4, 10, 200.000.

Odd numbers generate a remainder of 1: 1, 3, 5, 15…

You can check if a number is even or odd with an if conditional:

num = 3
if (num % 2) == 0:

If you have an array of numbers and want to get the ones even or odd, you can use filter() with a lambda function:

numbers = [1, 2, 3]

even = filter(lambda n: n % 2 == 0, numbers)
odd = filter(lambda n: n % 2 == 1, numbers)

print(list(even)) # [2]
print(list(odd)) # [1,3]
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