A regular expression to capture a URL without query string parameters
I had the need to capture a URL without query parameters.
For both http and https links.
Here’s the regex I used:
/^(http[^?#]+).*/gm
Here’s an example:
const regex = /^(http[^?#]+).*/gm
const result = regex.exec("https://test.com?test=2")
console.log(result)
/*
[ 'https://test.com?test=2',
'https://test.com',
index: 0,
input: 'https://test.com?test=2',
groups: undefined ]
*/
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